Follow the current NCERT path from unique prime factorisation through HCF, LCM and irrationality proofs, then finish every printed exercise.
Follow the numbered headings in order. Each parent section comes before its child subsections, matching the textbook path.
01
Core concept and worked examples
1.1-1.2 The Fundamental Theorem of Arithmetic
Use unique prime factorisation for HCF, LCM, ending-digit reasoning and the theorem needed for irrationality proofs.
Think of every composite number as a model built from prime-number bricks. You can rearrange the bricks, but you cannot secretly replace them with different prime bricks.
Section 1.1
Introduction
You already know Euclid's division algorithm from Class IX. This chapter now uses a different idea: prime factorisation. It helps us find HCF and LCM, test whether certain powers can end in zero, and prove irrationality.
The current chapter has two core ideas:
the Fundamental Theorem of Arithmetic
irrational numbers and proof by contradiction
Section 1.2
The Fundamental Theorem of Arithmetic
A prime number has exactly two positive factors: 1 and itself. A composite number has more than two positive factors.
Remember: The number 1 is neither prime nor composite.
The theorem says:
Fundamental Theorem of Arithmetic: Every composite number can be expressed as a product of primes, and this factorisation is unique apart from the order of the prime factors.
For example,
32760=23Ć32Ć5Ć7Ć13.
Writing the same primes in another order does not create a different factorisation.
Figure tracker
The factor tree on the opening pages breaks 32760 down to prime factors.
The Carl Friedrich Gauss box explains why the theorem is also called the unique factorisation theorem.
NCERT-matched schematic
Prime-factor tree
Chapter 1 opening factor tree
A simplified factor-tree redraw showing how one composite number reaches prime leaves.
1Composite number at the root
2A valid factor split
3Further composite branches
4Prime leaves that form the unique factorisation
Theorem 1.2
Let p be a prime number. If p divides a2, then p divides a, where a is a positive integer.
This result is used in the irrationality proofs in Section 1.3.
Example 1
Can 4n end with the digit 0 for a natural number n?
Solution:4n=22n. A number ending in 0 must contain both 2 and 5 in its prime factorisation. No factor 5 occurs, so 4n cannot end in 0.
Example 2
Find the HCF and LCM of 6 and 20 by prime factorisation.
Solution:6=2Ć3 and 20=22Ć5.
HCF=2,LCM=22Ć3Ć5=60.
For two positive integers a and b,
HCF(a,b)ĆLCM(a,b)=aĆb.
Example 3
Find the HCF of 96 and 404. Hence, find their LCM.
Solution:96=25Ć3 and 404=22Ć101.
HCF=22=4.
LCM=496Ć404ā=9696.
Example 4
Find the HCF and LCM of 6, 72 and 120.
Solution:6=2Ć3, 72=23Ć32, and 120=23Ć3Ć5.
HCF=2Ć3=6,
LCM=23Ć32Ć5=360.
Remember: The product rule for HCF and LCM is stated here for two positive integers. Do not apply it unchanged to three numbers.
ā ļø Common mistake
Common mistakes
stopping the factorisation while a composite factor remains
using largest powers for HCF instead of the smallest common powers
forgetting a prime that occurs in only one number while finding LCM
saying a power ends in zero without checking for both 2 and 5
š” Board tip
Board tips
Write the complete prime factorisation before selecting powers.
In an ending-zero question, connect the last digit to the factor 10=2Ć5.
In a proof, state the theorem or property you use; do not jump from pā£a2 to pā£a without reason.
āļø Quick practice
Quick practice
Write 3825 as a product of prime factors.
Find the HCF and LCM of 26 and 91.
Can 6n end in 0 for any natural number n?
š Practice feedback
Answer check
Try first, then reveal the answer
3825=32Ć52Ć17.
HCF =13 and LCM =182.
No. The factorisation of 6n has 2 and 3, but no 5.
ā±ļø 1-Minute revision
One-minute revision
Composite numbers have unique prime factorisations.
HCF takes the smallest common powers.
LCM takes the largest powers of all required primes.
A number ending in zero needs both 2 and 5.
š Memory strip
Comic recap
Quick scene, quick smile, quick memory. Read this once and the idea sticks better.
Memory strip
Panel 01Prime
I am one indivisible building brick.
Panel 02Composite
Break me fully before you stop.
Panel 03HCF
I keep only the common part.
Panel 04LCM
I collect enough prime powers for everyone.
02
Proof and reasoning lesson
1.3 Revisiting Irrational Numbers
Write complete contradiction proofs for square roots and rational-irrational combinations.
An irrational number cannot be written as qpā, where p and q are integers and qī =0. Its decimal form is non-terminating and non-repeating.
Section 1.3
Revisiting Irrational Numbers
You have already met 2ā, 3ā
ā ļø Common mistake
Common mistakes
not saying that a and b are coprime
proving only that a is divisible by the prime and forgetting b
writing "contradiction" without naming the contradiction
assuming every sum of two irrational numbers is irrational; for example, 2ā+(ā2ā)=0
š” Board tip
Board tips
Keep each implication on its own line.
End with a complete sentence: "This contradicts that a and b are coprime; therefore..."
For r+spā
āļø Quick practice
Quick practice
Prove that 5ā is irrational.
Explain why 75ā
š Practice feedback
Answer check
Try first, then reveal the answer
The same contradiction method forces both numerator and denominator to be divisible by 5.
If 75ā were rational, division by 7
ā±ļø 1-Minute revision
One-minute revision
Start with a lowest-form fraction.
A prime dividing a2 also divides a.
Force the same prime to divide numerator and denominator.
Name the contradiction and reject the assumption.
š Memory strip
Comic recap
Quick scene, quick smile, quick memory. Read this once and the idea sticks better.
Memory strip
Panel 01Assumption
Suppose the square root is rational.
Panel 02Theorem 1.2
A prime inside the square must divide its base.
Panel 03Contradiction
Both fraction parts share a factor!
Panel 04Conclusion
The lowest-form assumption fails, so the number is irrational.
03
Textbook practice
NCERT Exercises and Chapter Revision
Attempt both NCERT exercises before checking the factorisation, HCF-LCM and proof answers.
Try each printed exercise before opening its answer. A proof earns marks for its reasoned chain, not only its final line.
Exercise 1.1
1. Express each number as a product of its prime factors
Answer:
140=22Ć5Ć7
156=22Ć3Ć13
3825=32Ć52Ć17
5005=5Ć7Ć11Ć13
7429=17Ć19Ć23
2. Find the LCM and HCF of the following pairs and verify that LCM x HCF equals the product
Answer:
26,91: HCF =13, LCM =182
510,92: HCF =2
3. Find HCF and LCM by prime factorisation
Answer:
12,15,21: HCF =3, LCM =420
17,23,29: HCF =1
4. Given HCF(306,657)=9, find the LCM
Answer:
LCM=9306Ć657ā=22338.
5. Check whether 6n can end with digit 0
Answer: No. 6n=2n3n has no prime factor 5.
6. Explain why each expression is composite
Answer:
7Ć11Ć13+13=13(7Ć11+1)
7Ć6Ć5Ć4Ć3Ć2Ć1+5=5(7Ć6Ć4Ć3Ć2Ć1+1)
Each has a non-trivial factor.
7. Circular path meeting time
Answer: The friends take 18 and 12 minutes. They meet together at the starting point after LCM(18,12)=36 minutes.
Exercise 1.2
1. Prove that 5ā is irrational
Answer: Assume 5ā=a/b
Section 1.4
Summary
Every composite number has one prime factorisation apart from order.
If prime p divides a2, then p divides a.
ā ļø Common mistake
Common mistakes
multiplying before cancelling the HCF in an LCM calculation
treating the optional support topics as current numbered sections
giving only a one-line claim for an irrationality proof
Board-answer checklist
Have you shown prime factors clearly?
Have you used the correct HCF/LCM powers?
Have you stated "lowest form" and the final contradiction in every proof?
Active practice ladder
Write before checking
Exercise 1.1 active practice ladder
4 marks Ā· Attempt 1
1 Ā· Worked exampleFind the HCF of 96 and 404. Hence, find their LCM.
2 Ā· Similar question with hintsFind the LCM and HCF of 26 and 91 and verify that LCM Ć HCF equals the product of the two numbers.
ā±ļø 1-Minute revision
One-minute revision
Prime factorisation controls the arithmetic. Lowest-form contradiction controls the proofs.
š Memory strip
Comic recap
Quick scene, quick smile, quick memory. Read this once and the idea sticks better.
Memory strip
Panel 01Prime factors
We form one unique fingerprint.
Panel 02HCF
Take the shared smallest powers.
Panel 03LCM
Take all largest powers.
Panel 04Irrational proof
A shared factor breaks lowest form.
04
Unnumbered support concept
Support - Euclid Division Lemma
Review the Class IX division algorithm without treating it as current Chapter 1 board scope.
Scope note: This is an unnumbered Class IX support lesson. It is not a numbered core section of the current NCERT Class 10 Chapter 1 PDF or active 2026-27 board scope.
This lesson is a support lesson for the Real numbersAll numbers that fit somewhere on the number line.Example: -3, 0, 5/8, ā2 chapter. It helps us understand division properly first, so HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6. questions later do not feel scary.
Also, one small English help before we start: LemmaA small helpful rule used to prove or solve a bigger result.Example: Here it is the rule a = bq + r. means a small helpful rule. So do not panic. Big word, simple idea.
chapter start: what is a Real numberAny number that can be shown on the number line.Example: -3, 0, 5/8, ā2?
A Real numberAny number that can be shown on the number line.Example: -3, 0, 5/8, ā2 is any number that can be shown on the number line.
Examples:
5
0
-3
3/4
0.25
ā2
So yes, this chapter is about many kinds of numbers. Nice crowd.
quick warm-up: first see it the school way
When we divide 17 by 5, most Indian students think in long-division form first. That is the right starting point.
Animated walkthrough
Long-division warm-up
See the familiar school method first. Then map it to the equation form.
quotient?
divisor5
dividend17
We are dividing 17 by 5. This is the school-style layout most students already know.
From that long division, we get:
DividendThe number that is being divided.Example: In 17 Ć· 5, the dividend is 17. = 17
DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. = 5
QuotientThe answer we get before the remainder.Example: In 17 Ć· 5, the quotient is 3. = 3
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.
the rule in simple English
When a positive integer a is divided by another positive integer b, we can always write:
a = bq + r
where:
a is the DividendThe number that is being divided.Example: In 17 Ć· 5, the dividend is 17.
b is the DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5.
q is the QuotientThe answer we get before the remainder.Example: In 17 Ć· 5, the quotient is 3.
r is the RemainderThe part left after division.
what this really means
It simply means:
dividend = divisor Ć quotient + remainder
So this is not a new monster. It is just your old long division written in math language.
important condition
The RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. must always be smaller than the DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5..
Correct:
23 = 5 Ć 4 + 3
Wrong:
23 = 5 Ć 3 + 8
Why is the second one wrong? Because the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.8 is bigger than the DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5.
easy examples
example 1
Divide 20 by 6.
20 = 6 Ć 3 + 2
So:
QuotientThe answer we get before the remainder.Example: In 17 Ć· 5, the quotient is 3. = 3
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. = 2
example 2
Divide 35 by 7.
35 = 7 Ć 5 + 0
So:
QuotientThe answer we get before the remainder.
why this lesson matters in this chapter
This idea is used in the Euclid method for finding HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6. (Highest Common Factor).
Instead of doing FactorisationBreaking a number into smaller multiplying parts.Example: 12 = 2 Ć 2 Ć 3 for big numbers every time, we can keep dividing. That is often faster.
finding HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6. using Euclid's method
rule
Divide the bigger number by the smaller number.
Look at the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2..
If the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. is not 0, divide again.
In the next step, use the old DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5.
solved example 1
Find HCF(455, 42).
First write the steps:
Step 1:
455 = 42 Ć 10 + 35
Step 2:
42 = 35 Ć 1 + 7
Step 3:
35 = 7 Ć 5 + 0
Now see the same idea in long-division style.
Animated walkthrough
Euclid method animation
Notice how the old divisor and the remainder become the next division.
quotient10
divisor42
dividend455ā 420remainder = 35
Step 1: Divide the bigger number 455 by 42.
455 = 42 Ć 10 + 35
Now the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. is 0. So the last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. is 7.
Answer:
HCF(455, 42) = 7
solved example 2
Find HCF(135, 225).
Take the bigger number first.
225 = 135 Ć 1 + 90
135 = 90 Ć 1 + 45
90 = 45 Ć 2 + 0
Now the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. is 0, so stop. The last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. is 45.
Answer:
HCF(135, 225) = 45
how to think without fear
Many students get scared when they see many steps. Do not worry. Just remember this:
non-zero RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. ā divide again
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.0 ā stop
last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. ā answer
That is the whole game. No drama needed.
ā ļø Common mistake
common mistakes
Starting with the smaller number as DividendThe number that is being divided.Example: In 17 Ć· 5, the dividend is 17.
Forgetting to use the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. in the next step
Stopping one step too early
Writing the QuotientThe answer we get before the remainder.Example: In 17 Ć· 5, the quotient is 3. correctly but the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. wrongly
memory trick
Non-zero RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.? Divide again.
Old DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. and old RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. make the next division.
Remainder = 0? Stop.
Last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. gives the answer.
board tip
Write each division on a new line. Neat steps save marks. Messy steps donate marks to the examiner.
the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. must be smaller than the DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5.
to find HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6., keep dividing
if the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. is not 0
š Memory strip
Comic recap
Quick scene, quick smile, quick memory. Read this once and the idea sticks better.
Memory strip
Panel 01Remainder
I am not zero yet. One more round.
Panel 02Divisor
Fine. I will come back in the next step.
Panel 03Remainder = 0
Okay friends, show is over.
Panel 04Last divisor
Thanks. I am the HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6..
remember this line
Big number = divisor Ć quotient + what is left.
05
Unnumbered support concept
Support - Decimal Expansion of Rational Numbers
Review the denominator test without treating decimal expansion as current Chapter 1 board scope.
Scope note: This is an unnumbered support lesson. Decimal expansion is not a numbered core section of the current NCERT Class 10 Chapter 1 PDF or active 2026-27 board scope.
This lesson helps students connect fractions and decimals. It is one of the easiest parts of the chapter once the rule becomes clear.
start with a simple truth
A Rational numberA number that can be written in the form p/q where q is not 0.Example: 3/4, -7/5, 2, 0.125 can have:
a Terminating decimalA decimal that ends after a finite number of digits.Example: 0.325
or a Repeating decimalA decimal whose digits repeat in a fixed pattern forever.Example: 0.3333...
It will never become a non-repeating endless decimal. That kind of decimal is irrational.
examples first
Terminating decimalA decimal that ends after a finite number of digits.Example: 0.325
13/40 = 0.325
another Terminating decimalA decimal that ends after a finite number of digits.Example: 0.325
29/125 = 0.232
non-terminating Repeating decimalA decimal whose digits repeat in a fixed pattern forever.Example: 0.3333...
7/12 = 0.58333...
the main rule
First, write the fraction in Lowest formA fraction whose numerator and denominator have no common factor except 1.Example: 2/5 is the lowest form of 6/15.. Then look only at the denominator.
if the denominator has only Prime factorsFactors that are themselves prime numbers.Example: Prime factors of 12 are 2, 2, 3.2 and/or 5, the decimal terminates
if the denominator has any Prime factorA factor that is also a prime number.Example: 2 and 3 are prime factors of 12. other than 2 or 5, the decimal repeats
why 2 and 5 matter
Our decimal system is based on 10. And:
10 = 2 Ć 5
So denominators built from 2 and 5 fit nicely into decimal form.
do not skip Lowest formA fraction whose numerator and denominator have no common factor except 1.Example: 2/5 is the lowest form of 6/15.
This is very important. Always reduce the fraction first.
Example:
6/15
If you look directly at denominator 15, you may get confused. First reduce:
6/15 = 2/5
Now denominator is only 5. So the decimal terminates. In fact,
2/5 = 0.4
solved example 1
Check whether 13/40 terminates.
Factorise the denominator:
40 = 2³ à 5
Only 2 and 5 are present. So the decimal terminates.
Answer:
13/40 = 0.325
solved example 2
Check whether 7/12 terminates.
Factorise the denominator:
12 = 2² à 3
A Prime factorA factor that is also a prime number.Example: 2 and 3 are prime factors of 12.3 is present. So the decimal does not terminate. It repeats.
Answer:
7/12 = 0.58333...
solved example 3
Check whether 11/24 terminates.
Factorise the denominator:
24 = 2³ à 3
Since 3 is present, the decimal will not terminate. It will repeat.
solved example 4
Check whether 9/20 terminates.
Factorise denominator:
20 = 2² à 5
Only 2 and 5 are present. So the decimal terminates.
In fact,
9/20 = 0.45
ā ļø Common mistake
common mistakes
Not reducing the fraction to Lowest formA fraction whose numerator and denominator have no common factor except 1.Example: 2/5 is the lowest form of 6/15.
Looking at the numerator instead of the denominator
Forgetting that only 2 and 5 allow terminating decimals
Thinking a Repeating decimalA decimal whose digits repeat in a fixed pattern forever.Example: 0.3333... is irrational
Saying ānon-terminatingā without checking whether it repeats
memory trick
2 and 5 are friends of base 10.
board tip
If the question asks about decimal type, do not start long division first. Prime factorise the denominator. That is cleaner and faster.
compare these four cases
3/8: denominator 8 = 2³, so terminating
7/25: denominator 25 = 5², so terminating
5/6: denominator 6 = 2 Ć 3, so repeating
11/15: denominator 15 = 3 Ć 5, so repeating
āļø Quick practice
quick practice
Does 3/8 terminate or repeat?
Does 7/25 terminate or repeat?
Does 5/6 terminate or repeat?
Does 14/35 terminate or repeat after reducing to Lowest formA fraction whose numerator and denominator have no common factor except 1.Example: 2/5 is the lowest form of 6/15.?
š Practice feedback
Answer check
Try first, then reveal the answer
3/8 terminates because 8 = 2³
7/25 terminates because 25 = 5²
5/6 repeats because 6 = 2 Ć 3
14/35 = 2/5, so it terminates
ā±ļø 1-Minute revision
one-minute revision
first reduce the fraction to Lowest formA fraction whose numerator and denominator have no common factor except 1.Example: 2/5 is the lowest form of 6/15.
then FactoriseTo break a number into factors.Example: Factorise 12 as 2 Ć 2 Ć 3. the denominator
only 2 and 5 mean Terminating decimalA decimal that ends after a finite number of digits.Example: 0.325
any other Prime factorA factor that is also a prime number.Example: 2 and 3 are prime factors of 12.
š Memory strip
Comic recap
Quick scene, quick smile, quick memory. Read this once and the idea sticks better.
Memory strip
Panel 01Denominator
Please check me first. I am the main character here.
Panel 02Recap
2 and 5: āWe are decimal-friendly friends.ā
Panel 033
If I enter the denominator, the decimal keeps repeating.
Panel 04Student
So first reduce, then check denominator. Got it.
remember this line
If the denominator has only 2 and 5, the decimal ends. If not, it repeats.
,
5ā
and many similar numbers. Here the goal is to prove irrationality with the Fundamental Theorem of Arithmetic.
Proof by contradiction
The method has five steps:
Assume the opposite of what you want to prove.
Write the assumed rational number in lowest form.
Use algebra and Theorem 1.2.
Reach a fact that contradicts "lowest form".
Reject the assumption and state the conclusion.
Theorem 1.3: 2ā is irrational
Assume 2ā is rational. Then
2ā=baā,
where a and b are coprime positive integers.
Squaring gives a2=2b2. So 2 divides a2, and Theorem 1.2 gives 2ā£a. Let a=2c.
Substitution gives 4c2=2b2, so b2=2c2. Hence 2ā£b.
Both a and b are even. This contradicts the assumption that they are coprime. Therefore, 2ā is irrational.
Example 5
Prove that 3ā is irrational.
Solution: Assume 3ā=baā in lowest form. Then a2=3b2, so 3ā£a. Put a=3c. This gives b2=3c2, so 3ā£b. The common factor 3 contradicts lowest form. Therefore, 3ā is irrational.
Rational and irrational combinations
rational + irrational is irrational
rational ā irrational is irrational
non-zero rational Ć irrational is irrational
irrational Ć· non-zero rational is irrational
These rules are used only when the rational multiplier or divisor is non-zero.
Example 6
Show that 5ā3ā is irrational.
Solution: If 5ā3ā were rational, subtracting it from the rational number 5 would make 3ā rational. That contradicts Example 5. Hence 5ā3ā is irrational.
Example 7
Show that 32ā is irrational.
Solution: If 32ā were rational, dividing it by the non-zero rational number 3 would make 2ā rational. This is impossible. Hence 32ā is irrational.
, isolate the irrational term instead of repeating the full square-root proof.
is irrational.
Explain why 6+2ā is irrational.
would make
5ā
rational.
If 6+2ā were rational, subtracting 6 would make 2ā rational.
, LCM
=23460
336,54: HCF =6, LCM =3024
, LCM
=11339
8,9,25: HCF =1, LCM =1800
in lowest form. The equation
a2=5b2
forces
5ā£a
and then
5ā£b
, contradicting lowest form.
2. Prove that 3+25ā is irrational
Answer: If it were rational, subtracting 3 and dividing by 2 would make 5ā rational, a contradiction.
3. Prove that the listed numbers are irrational
Answer:
1/2ā: otherwise its reciprocal 2ā would be rational.
75ā: otherwise division by 7 would make 5ā
6+2ā: otherwise subtraction of 6 would make 2ā
The contradiction proof shows 2ā, 3ā and 5ā are irrational.
Note to the Reader
For three positive integers, the textbook gives separate HCF and LCM relations. Do not extend the two-number product rule without checking the stated formula.
=
2
Now write the same idea in one line:
17 = 5 Ć 3 + 2
So the long-division picture and the equation are saying the same thing.
Example: In 17 Ć· 5, the remainder is 2.
0 ⤠r < b
5
.
Example: In 17 Ć· 5, the quotient is 3.
=
5
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. = 0
When RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. is 0, the division is exact.
and the old
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.
.
When the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. becomes 0, stop.
The last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. gives the HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6..
Giving the
RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2.
as the final
HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6.
, divide again
when the RemainderThe part left after division.Example: In 17 Ć· 5, the remainder is 2. becomes 0, the last DivisorThe number by which we divide.Example: In 17 Ć· 5, the divisor is 5. is the HCFHighest Common Factor: the biggest common factor of the given numbers.Example: HCF of 12 and 18 is 6.
means
Repeating decimalA decimal whose digits repeat in a fixed pattern forever.Example: 0.3333...